a) Write a balanced chemical equation for the combustion of pentane. C5H12 + 8O2 -----> 5CO2 + 6H20 Roger the Mole. What is the maximum amount of product that should be produced from a given amount of reactant? expected yield. What is the reducing agent? 2.5001 moles of O2 would react … 9 years ago. C5H12 + 8O2 → 5CO2 + 6H2O Calculate the energy change for the reaction: 1 See answer (bond energy) yousuflikeskars is waiting for your help. 4 NH3 + 5 O2 → 4 NO + 6 H2O (80.0 g O2) / (31.99886 g O2/mol) = 2.5001 mol O2 (70.0 g NH3) / (17.03056 g NH3/mol) = 4.1103 mol NH3. If 5.93 moles of C 5 H 12 reacts with excess O 2, how many moles of CO 2 will be produced in the following combustion reaction? So there has to be 5 carbons and then 6 hydrogens (12/2 =6) . C 5 H 12 + 8O 2 → 6H 2 O + 5CO 2. C5H12 + 8O2 → 6H2O + 5CO2. Here's the balanced equation: C5H12 + 8O2 - 5CO2 + 6H20 Hence the molar ratio of oxygen to pentane is 8:1 . 2 Answers. 2 Answers. Favorite Answer. ,v wkh surfhvv ri exuqlqj wkh frpelqdwlrq ri dq rujdqlf vxevwdqfh zlwk r[\jhq wr surgxfh d iodph :khq dq rujdqlf frpsrxqg exuqv lq r[\jhq wkh fduerq uhdfwv zlwk r[\jhq wr irup &2 C5H12 + 8O2 → 6H2O + 5CO2. Lv 7. The rate of a chemical reaction is defined as the rate of change in concentration of a reactant or product divided by its coefficient from the balanced equation. Limiting Reactant. You cant reduce it because 5, 6, and 8 aren't factorable together. 2.5001 moles of O2 would react … 164 g. What mass of SiF4 could be produced by the reaction of 15 g of SiO2 with an excess of HF? 1C5H12 + 8O2 --> 5CO2 + 6H2O. Related questions. C 5 H 12 + 8O2 → 6H 2 O + 5CO 2. C5H12 + 8O2 -----> 6H2O + 5CO2. C5H12 (l) + 8O2 (g)~ 5CO2 (g) + 6H2O (g) a. a. When pentane, C5H12, is combusted in air, the products are carbon dioxide and water. Chemistry When a mixture of 13.0 g of acetylene (C2H2) and 13.0 g of oxygen (O2) is ignited, the resultant combustion reaction produces CO2 and H2O. How many grams of H2O will you make? 6 moles b. Log in or register to post comments; Similar Questions. First Name. So all that was left was to add 8 in front of O2 on reactant side. 92.8 g of CO2 . Learn this topic by watching Stoichiometry Concept Videos. Then we need to determine which choice, A or C, is correctly balanced. Relevance. Asked: How many moles of H2O can be formed with 0.200 mol of C5H12. Sep 25, 2013 . 2 Answers. can you please please help me … Question #fee47 Question #c5c15 Question #19eb9 Question #e2ea2 Question #bc751 Question #e2ea6 Question … 22.05 = 22.1 sig fig 0 0; Pat. you initially had 16 oxygen molecules on the reactant side. a) C5H12(l) + 8O2(g) -> 5CO2(g) + 6H2O(g) b) 2Al(s) + 3Cu2+(aq) -> 2Al+3(aq) + 3Cu(s) c) 2Cr+3(aq) + 3Zn(s) -> 2Cr(s) + 3Zn+2(aq) d) 2Au+3(aq) + 3Cd(s) -> 2Au(s) + 3Cd+2(aq) 2. Grace Nov 9, 2015 #C_5H_12 + 8# #O_2 -> 6# #H_2O + 5# #CO_2# Answer link. Then you add in the remaining oxygens. Answer Save. The reactants are Li and O2. ★★★ Correct answer to the question: Using the equation, c5h12 + 8o2 imported asset 5co2 + 6h2o, if an excess of pentane (c5h12) were supplied, but only 4 moles of oxygen were available, how many moles of water would be produced? Thus the equation is given below: Li + O2 —> Li2O. 2 Answers. If 7.65 moles of C 5 H 12 reacts with excess O 2, how many moles of CO 2 will be produced in the following combustion reaction? 4 NH3 + 5 O2 → 4 NO + 6 H2O (80.0 g O2) / (31.99886 g O2/mol) = 2.5001 mol O2 (70.0 g NH3) / (17.03056 g NH3/mol) = 4.1103 mol NH3. for the given equation C5H12+8O2->5CO2+6H2O: if the reactant C5H12 and O2 are having 2 moles and 8 moles initially a) Which is Excess reactant? 1. Calculate the molarity of the solution. so, to balance the 16 oxygen molecules on the product side, you use 8 O2 molecules. Answers (2) Zackary Willis 3 November, 15:12. it's easiest to leave the oxygen last as it is the only element that is not part of a compound element. How many grams of H2O will you make? 1. Limiting reagent: Compound: Coefficient: Molar Mass: Moles: Weight: C 5 H 12: 5: 72.14878: O 2: 25: 31.9988: CO 2: 25: 44.0095: H 20: 3: 20.1588: Units: molar mass - g/mol, weight - g. Please tell about this free chemistry software to your friends! If 4.36 moles of C5H12 reacts with excess O2, how many moles of CO2 will be produced in the following combustion reaction? How many moles of O2 needed to produce 11.5 grams of CO2? This made Hydrogen balance also, and it gave oxygen a 16 on product side. c) How many grams of water is formed at the end of the reaction How many ml of 6.00 m naoh is needed to prepare 250 ml of 0.600 m naoh? Roger the Mole. C5H12 + 8O2 --> 5CO2 + 6H2O You start with 150.0 g of pentane and 500.0 L of O2. C5H12(g)+8O2(g)→5CO2(g)+6H2O(g) Calculate the mass of CO2 that can be produced if the reaction of 38.5 g of pentane and sufficient oxygen has a 58.0 % yield. How many grams of O2 are required to burn 46.0 grams of C5H12? C5H12 + 8O2 → 5CO2 + 6H2O 2 See answers sdmatera sdmatera We can first rule out choices B and D because in decomposition reactions, one reactant is decomposed or broken up to form two or more products. FeS 2HCl FeCl2 H2S 8 copperII hydroxide acetic acid Copper2 Acetate water CuOH2 from SCIENCE CHE121 at Truett McConnell University Thus the equation is balanced as follow: There are 2 atoms of O on the left side and 1 atom on the right side. Favourite answer. Similar Questions. I have the answers but need help on how to work the problems out please. On the product side you have CO2 and H2O. Given: C5H12+8O2→5CO2+6H2O 0.200 mol C5H12. 1:6 6:8 8:1 10:8 . : 872 times balanced equation: C5H12 + 8O2 — > Li2O formation and delta post. 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